I have a procedure that creates two files only one of theses files is created at a time depending on if there was an error or not, what I need to do is to search a specified directory and pickup the name of the file that is in there and then be able to store this a a variable so that the script can then just pass in the variable to see which script to run next.

I have tried something like this

#!/bin/bash

for file in 'ls /u1/dev/procedures/sales/*.sh'; do
echo $file
done

###########

but all i get returned is

'ls /u1/dev/procedures/sales/<filename>.sh'

All I need returned is just the filename.
 

Do a man on

basename
dirname
 

You don't need 'ls' or quotes. Try:
for file in /u1/dev/procedures/sales/*.sh
do
echo $file
done

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