Trying to write a script that renames a logfile if it exceeds roughly 1 MB.

My find command is:

Code:

find some_logfile -type f -size +20000

Now I want to do my processing if it finds a file or not...
How can I go about this? The $? is 0 if it finds a file or not.

Solution:

Please avoid running scripts containing errors in a production environment. It will bite you in the bum.

Here is a script structure which you may wish to amend to your local environment. 

Please avoid blind cut/paste/run because you need to understand what is going to happen before you run a script.

There are several riders regarding logfile maintenance scripts. If the logfile is open by a program do not rename (mv) the file. In certain circumstances you can copy then truncate the logfile, in other circumstances you must ensure that the program does not have the logfile open. It is all to easy to crash a database engine by renaming logs.

Code:

filename="some_logfile"
MB="`echo '1024 * 1024'|bc`"    # One megabyte in bytes
#
# If the file exists, find out how big it is in bytes
if [ -f "${filename}" ]
then
        filesize=`ls -lad "${filename}" | awk '{print $5}'`
else
        echo "File missing: ${filename}"
        exit 1
fi
#
# Compare the size of the file with the maximum and rename the file if it is too big
if [ ${filesize} -gt ${MB} ]
then
        echo "Renaming ${filename} ${filename}.old"
        mv "${filename}" "${filename}.old"
fi

or 

I don't know whether my understanding is correct on your requirement. But you can achieve this by a single stroke .

Code:

find . -iname "test_log" -size +1M -exec mv {} test_log_mbs \;

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