Using find and grep together:

To find all files with target pattern in any given directory use the command:

% find [target_dir] -exec grep -l 'target' {} \;

This uses the find fuction with the grep function to specify absolute path to all files with the target pattern in them.

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I want to searh a record in the table. But I don't want to display out the entire row or column record. What I want to display is only a single row or column record.

I have try grep ann file-name what should I add so I can display the row 4 record that I have.

The following command display the column 4 of the forst line of the input file containing 'ann' :

awk '/ann/ {print $4;exit}' input_file

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Is there any method that u know using grep instead of using awk to the example above.

I'm using "grep ann inputfile" and it show all the entire row and not the record on column 4.

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The short answer is - no. The grep utility is a line orientated utility. You can use grep to find/print the line but you then
need to use some other utility (cut/awk, etc.) to process the line and only output the part of the line that you want.

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There is a way of doing it.
Why don't you post your homework assignment so I can verify my procedure is in conformance with your assignment.

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This is my example:

name age number (not list in the file)
acb 51 1234
hela 42 4567

My question is that now I know how to cut the column already but when I cut it I want to use grep to display out the age that less than 50, how should use grep to search age that less than 50.

I have try using grep [:digit:] < 50 file but I fail to do this.

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cut -d\ -f2 example |grep -E "^[0-9]$|^[0-4][0-9]$"

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Of course, that takes advantage of 50 being a multiple of 10. <54 would be a bit hairy'er.
This will handle any number:
NUM=50 # for example
cat example| while read a b c;do [ $b -lt $NUM ] && echo $b;done

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Sorry for posting againt but still not very understand, how about I using grep to compare column 3 record (exp: < 25.50) and display record at column 1 and 3 that match the requirement using grep.

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"compare column 3 record" or column 2 ??
" using grep" why grep ??

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To display all rows in test.dat where the value in the second column is less than 50:
awk '{ if ($2 < 50) {print} }' test.dat

As others have pointed out, grep is a tool for pattern filtering, not output manipulation.

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