P5 Maths Worksheets Singapore - Problem Questions Revision 9
 

Name : ____________________    Date   : _____________

                                                          Score : _____________

Write down your correct answer and show your workings:

  1) The cost of a camera and a watch was $2200. 
      The usual price of the camera was 20% more than its cost and the usual price of the watch was 10% more than its cost. 
      During a promotion, both items were given a 10% discount of their usual price. 
      As a result, there was a profit of $131. What was the cost of the camera? 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

    Ans: ____________________
 

  2) An aquarium owner sold 98 rainbow fish on the first day and earned a profit of $44.10 for each of the rainbow fish sold. 
      On the second day, 133 rainbow fish were sold and the aquarium owner gained a profit of 40% of the cost. 
      If the money collected on both days were the same, how much did each rainbow fish cost?
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

    Ans: ____________________
 

 3) Danny had $156 more than Esther. 
     After Danny had spent 1/6 of his money and Esther spent 1/2 of her money, 
     Danny had $245 more than Esther. 
     How much money did Danny have at first?
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

    Ans: ____________________
 

  4) The ratio of John's cards to Ben's cards was 3:4 
      After John bought another 9 cards and Ben lost 18 cards, the ratio was 3:2
      Find the total number of cards they had at first respectively.?
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

    Ans: ____________________
 

  5) A concrete mixer has a mixture of cement and sand. 
      If 5.3 litres of cement were added, 75% of the mixture would be sand.
      If 57.8litres of cement were added, 40% of the content will be sand.
      Find the volume of cement in the mixture.
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

    Ans: ____________________
 
 


Answers:

1) 
Camera 

Cost Price ------ 100 units
Usual Price ----- 120 units
Promotion price ------108 units

Watch

Cost Price ------ 100 parts
Usual Price ----- 110 parts
Promotion price ------ 99 parts

100 units + 100 parts ------ 2200
108 units + 99 parts ------ 2331

1 unit + 1 part ------ 22

9 units + 99 units + 99 parts ----- 2331
9 units + (99*22) ------ 2331

1 unit ----- 17 (Workings: (2331 - 2178) / 9)

Hence 1 part -----5

Cost of camera = 17 x 100 = 1700

2)
First day

Profit earned ------ 98 x 44.10 ------ 4321.80

Second day

CP per fish ----- 10 units
SP per fish ----- 14 units

Total selling price -----133 x 14 ------ 1862 units

1862 units ----- 980 units + 4321.8
1 unit ----- 4.9

CP per fish =  4.9 x 10 =  49
 
3)           1u    1u    1u    1u    1u    1u      Danny mony left = 5u + $130
Danny    26     26   26     26    26    26      156 / 6 = $26 

Esther     1u    1u    1u    1u    1u    1u   Esther money left = 3u

In the end, Danny had $245 more than Esther.
 
So, 5u + $130 = 3u + $245
2u = $115

At first, Danny had 6u + $156
= 3 x $115 + $156
= $501

Danny had $501 at first.

4)
J:B
3u:4u
+9:-18
3p:2p

3u+9=3P
4u-18=2p

Hence 6u+18=6p
12u-54=6p

6u+18=12+54
U=12

J=3*12=36
B=4*12=48

5)
The volume of cement in the mixture
7u = 52.5 L
1u = 7.5 L

Volume of cement in mixer
= 2u - 5.3 L
= 15 L - 5.3 L
= 9.7 L

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